Newton's law of gravitation is:

$$F = G m_1 m_2 \frac{1}{r^2}$$

It looks simple and natural.

But that's only in 3 dimensions. Let's look what happens in n dimensions:

$$n=2 : F = 2 G m_1 m_2 \frac{1}{r}$$

$$n=4 : F = \frac{2}{\pi} G m_1 m_2 \frac{1}{r^3}$$

$$n=5 : F = \frac{3}{2 \pi^2} G m_1 m_2 \frac{1}{r^4}$$

$$n=6 : F = \frac{4}{\pi^2} G m_1 m_2 \frac{1}{r^5}$$

Oh no! Newton's law of gravitation becomes ugly, weird and incomprehensible.

But by posing $$G^* = 4 \pi G$$ Newton's law of gravitation can be reformulated as such:

$$F = G^* m_1 m_2 \frac{1}{4 \pi r^2}$$

Immediately we recognize that $$4 \pi r^2$$ is simply the surface area of a sphere of radius r.

But that's only in 3 dimensions. Let's look what happens in n dimensions:

$$n=2 : F = G^* m_1 m_2 \frac{1}{2 \pi r}$$

$$n=4 : F = G^* m_1 m_2 \frac{1}{2 \pi^2 r^3}$$

$$n=5 : F = G^* m_1 m_2 \frac{1}{\frac{8}{3} \pi^2 r^4}$$

$$n=6 : F = G^* m_1 m_2 \frac{1}{\pi^3 r^5}$$

$$2 \pi r$$ is the surface area of a 2 dimensional sphere of radius r.

$$2 \pi^2 r^3$$ is the surface area of a 4 dimensional sphere of radius r.

$$\frac{8}{3} \pi^2 r^4$$ is the surface area of a 5 dimensional sphere of radius r.

$$\pi^3 r^5$$ is the surface area of a 6 dimensional sphere of radius r.

Newton's law of gravitation in n dimensions is:

$$F = G^* m_1 m_2 \frac{1}{S_n}$$

Where $$S_n$$ is simply the surface area of a n dimensional sphere of radius r.

This proves that $$G^* = 4 \pi G$$ is the true most fundamental gravitational constant, not G.

Am I a genius or what?

Now I will begin to create my new system of measurement, based on dozenal and natural units.

$$c = \hbar = 4 \pi G = \epsilon_0 = k_B = 1$$

$$F = G m_1 m_2 \frac{1}{r^2}$$

It looks simple and natural.

But that's only in 3 dimensions. Let's look what happens in n dimensions:

$$n=2 : F = 2 G m_1 m_2 \frac{1}{r}$$

$$n=4 : F = \frac{2}{\pi} G m_1 m_2 \frac{1}{r^3}$$

$$n=5 : F = \frac{3}{2 \pi^2} G m_1 m_2 \frac{1}{r^4}$$

$$n=6 : F = \frac{4}{\pi^2} G m_1 m_2 \frac{1}{r^5}$$

Oh no! Newton's law of gravitation becomes ugly, weird and incomprehensible.

But by posing $$G^* = 4 \pi G$$ Newton's law of gravitation can be reformulated as such:

$$F = G^* m_1 m_2 \frac{1}{4 \pi r^2}$$

Immediately we recognize that $$4 \pi r^2$$ is simply the surface area of a sphere of radius r.

But that's only in 3 dimensions. Let's look what happens in n dimensions:

$$n=2 : F = G^* m_1 m_2 \frac{1}{2 \pi r}$$

$$n=4 : F = G^* m_1 m_2 \frac{1}{2 \pi^2 r^3}$$

$$n=5 : F = G^* m_1 m_2 \frac{1}{\frac{8}{3} \pi^2 r^4}$$

$$n=6 : F = G^* m_1 m_2 \frac{1}{\pi^3 r^5}$$

$$2 \pi r$$ is the surface area of a 2 dimensional sphere of radius r.

$$2 \pi^2 r^3$$ is the surface area of a 4 dimensional sphere of radius r.

$$\frac{8}{3} \pi^2 r^4$$ is the surface area of a 5 dimensional sphere of radius r.

$$\pi^3 r^5$$ is the surface area of a 6 dimensional sphere of radius r.

Newton's law of gravitation in n dimensions is:

$$F = G^* m_1 m_2 \frac{1}{S_n}$$

Where $$S_n$$ is simply the surface area of a n dimensional sphere of radius r.

This proves that $$G^* = 4 \pi G$$ is the true most fundamental gravitational constant, not G.

Am I a genius or what?

Now I will begin to create my new system of measurement, based on dozenal and natural units.

$$c = \hbar = 4 \pi G = \epsilon_0 = k_B = 1$$